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EastWind [94]
3 years ago
7

You need a 45% alcohol solution. On hand, you have a 175 mL of a 25% alcohol mixture. You also have 70% alcohol mixture. How muc

h of the 70% mixture will you need to add to obtain the desired solution?
Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0

175 mL at 25% concentration of alcohol contains 0.25 (175 mL) = 43.75 mL of alcohol. If <em>v</em> is the amount of the 70% solution that you use, then that amount contains 0.7<em>v</em> mL of alcohol.

Mixing these two yields a total volume of 175 mL + <em>v</em>, and it contains 43.75 mL + 0.7<em>v</em> alcohol. You want to end up with a concentration of 45%, which means the ratio of the amount of alcohol to the total volume needs to be 0.45:

(43.75 mL + 0.7<em>v</em>) / (175 mL + <em>v</em>) = 0.45

Solve for <em>v</em> :

43.75 mL + 0.7<em>v</em> = 0.45 (175 mL + <em>v</em>)

43.75 mL + 0.7<em>v</em> = 78.75 mL + 0.45<em>v</em>

0.25<em>v</em> = 35 mL

<em>v</em> = 140 mL

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