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3 years ago

If the outlier is removed, which measure will not change? A.range B.mode C.median D.mean

Mathematics

1 answer:

kramer3 years ago

3 0

C. median

Because the middle will still be the same, but the rest of them (mean, mode, range) will change.

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PLEASE HURRY!!!!!!!!!

kari74 [83]

Answer:

Mean: 16.

Step-by-step explanation:

—Mean—

13 14 14 16 16 16 16 18 18 19

Simply start by adding the numbers together.

13 + 14 + 14 + 16 + 16 + 16 + 16 + 18 + 18 + 19

= 160.

Then divide it by how many numbers there are. Which is 10.

160 divided by 10 = 16.

—MAD—

Subtract each number by the mean.

|13-16| + |14-16| + |14-16| + |16-16| + |16-16| +|16-16| + |16-16| + |18-16| + |18-16| + |19-16|

Negatives don’t matter, everything should be positive numbers.

3 + 2 + 2 + 0 + 0 + 0 + 0 + 2 + 2 + 3

= 16

16 divided by 16 (amount of numbers).

MAD = 1

–IQR—

Seperate both sides in half.

|13 14 14 16 16| |16 16 18 18 19|

Take the median of each group.

Group 1:

|13 14 (14) 16 16|

This one is 14.

Group 2:

|16 16 (18) 18 19|

This one is 18.

Now take (number from group 2) 18 and subtract by (number from group 1) 14.

18 - 14 = 4

IQR = 4.

4 0

4 years ago

Find g(4) for g(t) =5t^2

faust18 [17]

Answer:

g(4) = 80

Step-by-step explanation:

g(t) =5t^2

let t=4

g(4) = 5* 4^2

g(4) = 5 * 16

g(4) = 80

5 0

4 years ago

What percent of 380 is 190?

marishachu [46]

50% of 380 is 190
Mark brainliest

7 0

3 years ago

Read 2 more answers

Use a power series to approximate the value of the integral with an error of less than 0.0001. (Round your answer to four decima

otez555 [7]

Answer:

The answer is "0.9461"

Step-by-step explanation:

Given:

$\int^1_0 \frac{sin(x)}{x} dx\\\\$

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $\sum^2_{n=0}\frac{(-1)^n x^{2n+1} (-1)^n (x-1)^n}{(2n + 1)!}$

$\therefore$

$\to \sin x = \sum^{\infty}_{n=0} (-1)^n\frac{x^{(2n+1)}}{(2n + 1)!}$

$\because \\\\ \to \frac{\sin x}{x} =\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1-1}}{(2n+1)!}\\$

$=\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n}}{(2n+1)!}$

The value is in between 0 and 1 then:

$\to \int^1_0 \frac{sin(x)}{x} = =\sum^{2}_{n=0} \frac{(-1)^n}{ (2n+1) (2n+1)!}$

The above-given series is an alternative series, and it will give an error, when the nth term is bounded by its absolute value, that can be described as follows:

$\to \frac{1}{(2n+3) (2n+3)!}< 0.0001\\\\\to (2n+3) (2n+3)!> 0.0001\\\\\to n\geq 2 \\$

So,

$\int^1_0 \frac{sin(x)}{x} dx\\\\$ ≈ $1 - \frac{1}{3 \cdot 3!}+\frac{1}{5 \cdot 5!}\\\\$

$\approx 1 - \frac{1}{3 \cdot 6}+\frac{1}{5 \cdot 120}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx 1 - \frac{1}{18}+\frac{1}{600}\\\\\approx \frac{18-1}{18}+\frac{1}{600}\\\\\approx \frac{17}{18}+\frac{1}{600}\\\\\approx \frac{1700+3}{1800}\\\\ \approx \frac{1703}{1800}\\\\\approx 0.9461$

5 0

3 years ago

What does this equal =

lana [24]

The equation is y=mx+c, in which m is the slope(1/2), c is the y intercept (5), and x is the x intercept (0)
thus, the equation is:
y=(1/2)(0)+5
y=5

hope it helps!

7 0

4 years ago