All categories

3 years ago

What is the constant variation in the equation 3y=6x? Explain. PLEASE HELP IM DESPERATE

Mathematics

1 answer:

pshichka [43]3 years ago

4 0

Write in slope intercept form

y=2x

the constant variation (slope) can readily be read now. it's 2

You might be interested in

If 6 is added to twice a number and the sum is multiplied by 5 the result is the same as if the number is multiplied by -18 and

exis [7]

5(2x+6)=-18x+2
10x+36=-18x+2
28x=-34
x= $\frac{-34}{28}$
x= $\frac{-17}{14}$

6 0

4 years ago

Anna is holding a party for six children. She buys cupcakes which come in boxes of four. The children eat all the cupcakes and t

Karolina [17]

Anna could have bought 3 boxes, which would serve 2 cupcakes to each child.

8 0

3 years ago

Read 2 more answers

There are 30 colored marbles inside a bag. Six marbles are yellow, 9 are red, 7 are white, and 8 re blue, One is drawn at random

Ratling [72]

Answer:

Red

Step-by-step explanation:

Of the specific numbers of each color, red has the most marbles, so mathematically speaking, red has the highest chance of being chosen first

Hope this helps!

6 0

3 years ago

Read 2 more answers

A dwarf sea horse swims 3/4 inch in a minute. how many minutes would it take a seahorse to swim 1/3 of a inch?

kiruha [24]

Answer:

0.25

Step-by-step explanation:

maybe this will work .

5 0

3 years ago

Find the points of intersection of the lines 10x−4y=2 and 2x+8y=7 without graphing.

Jet001 [13]

Answer:

$x=\frac{1}{2},y=\frac{3}{4}$

Step-by-step explanation:

Given:

$10x-4y=2 ,2x+8y=7$

To find: points of intersection of the given lines

Solution:

In substitution method, the system of equations is solved by expressing one variable in terms of another, as a result, removing one variable from an equation.

$10x-4y=2 \\2(5x-2y)=2\\5x-2y=1\\5x=1+2y\\x=\frac{1+2y}{5}$

Put $x=\frac{1+2y}{5}$ in the equation $2x+8y=7$

$2x+8y=7\\2[\frac{1+2y}{5}]+8y=7\\ 2+4y+40y=35\\44y=35-2\\44y=33\\y=\frac{33}{44}\\ =\frac{3}{4}$

Put $y=\frac{3}{4}$ in the equation $x=\frac{1+2y}{5}$

$x=\frac{1+2y}{5}\\=\frac{1}{5}[1+2(\frac{3}{4})]\\=\frac{1}{5}[1+(\frac{3}{2})]\\\\=\frac{1}{5}(\frac{2+3}{2}) \\\\=\frac{1}{5}(\frac{5}{2})\\\\=\frac{1}{2}$

Therefore,

$x=\frac{1}{2},y=\frac{3}{4}$

5 0

3 years ago