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3 years ago

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. n an 1 5 2 −10 3 20

Mathematics

1 answer:

Alenkinab [10]3 years ago

4 0

Answer:

The answer to this would be 662.

Step-by-step explanation:

Sigma notation calls for the sum of the terms in the sequence.

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Consider the polynomial equation x(x-3)(x+6)(x-7)=0. Which of the following are zeroes of the equation? Select all that apply.

Marina CMI [18]

If looking for the answer it would be 0, 3, -6, 7

6 0

3 years ago

I NEED HELP!!

Bess [88]

<h2>Answer:</h2>

4x - 6 + 2x = 3(2x - 2)

4x - 6 + 2x = 6x - 6

[ both sides - 6 cancel each other ]

4x + 2x = 6x

6x = 6x

[ both sides 6x cancel each other ]

0 = 0.

4 0

3 years ago

Read 2 more answers

During a sale at a bookstore, a customer buys one book at full price. The customer is given a 25 percent discount on a second bo

RoseWind [281]

Amount paid for the first book is $17.

Amount paid for the second book is 0.75 x 8 = $6

Total amount paid = $17 + $6 = $23

Total full cost of the two books = $17 + $8 = $25

Amount of discount = $25 - $23 = $2

% reduction = $\frac{2}{25} \times100\%=8\%$

Therefore, the <span>percent of the total cost of the two books reduced during the sale</span> is 8%

6 0

3 years ago

Read 2 more answers

Please help thanks :)

kykrilka [37]

Question 1:

Multiply both sides of the proportion by 35.

You get.

7(x-1) = 4x+2

7x-7 = 4x+2

Now, add both sides by 7 and subtract both sides by 4x

3x = 9

Divide both sides by 3

x=3

Question 2:

Multiply both the numerator and the denominator of $\frac{x+1}{x+3}$ by 3.

We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.

$\frac{3x+3}{3x+9} = \frac{15}{21}$

Set the numerator equal to the numerator and the denominator equal to the denominator.

3x+3 = 15

3x+9 = 21

If you solve both of these, you get x=4 for both.

That's your answer.

Hope this helps! :)

8 0

3 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago