A semicircle and a quarter circle are attached to the sides of a rectangle as shown. What is the area of this figure? Use 3.14 f
1 answer:
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Answer:
To find the surface area of this pyramid, we must find the <u>area</u> of one <u>triangle</u> flap which we then <u>multiply by 4</u> because there are 4 of those equal triangle flaps surrounding the base(square). Once we find the area of those triangles, we then find the <u>base(square)'s area</u>. Next, we add all those areas together to get the result of the surface area.
Formula for area of triangle;
A = BH x 1/2
Where 'B' represents the base, 'H' represents the height, and 1/2 is just dividing the product of those two lengths by 2.
Plug in what you know, given that the base of one triangle is 4, and the height is 6.
A = 4(6) x 1/2
A = 24 x 1/2
A = 24/2
A = 12, the area of <em>one triangle is 12 inches</em>.
Now, we find the area of all the triangles by multiplying the area of one triangle by 4.
12 = Area of triangle
4 triangles in total, so:
12(4)
= <u>48 inches</u> is the <u>area</u> of <u>all the triangles</u>.
Now we find the area of the base(square) using the formula;
(vol of square formula)
A =
Where 's' represents one side of the square which is being squared.
or
A = l · w
Where 'l' represents the length and 'w' represents the width.
Plug in what you know, given that one side of the square is 4 inches (as well as the length and width).
(I'll be using the formula )
A =
A = 4^2 ← (The symbol ' ^ ' means raised to the power of.)
A = 16, the <u>area</u> of the <u>base(square)</u> is <u>16 inches</u>.
Now we add both areas together:-
48 + 16
= <u>64 inches^2</u> is the surface area, your answer is A.
Answer:
∠B ≅ ∠Y △ABC ~ △ZYX by the SAS similarity theorem.
Step-by-step explanation:
1. units
units
units
units, then
2. and
are right angles - given
3. two right angles are always congruent.
4. by SAS similarity theorem.
SAS Similarity Theorem states that if two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.