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3 years ago

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A semicircle and a quarter circle are attached to the sides of a rectangle as shown. What is the area of this figure? Use 3.14 f

or pi. PLEASE HELPPP!!

1 answer:

Serjik [45]3 years ago

5 0

Answer:

need picture but i was in same quiz 109

Step-by-step explanation:

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2 years ago

PERSONALLY I thought it would be 98 Bc like yk..BUT I FEEL LIKE IM WRONGsend help beggin cryin throwin up I hate geometry so muc

Talja [164]

Answer:

98

Step-by-step explanation:

It is 98! x and the 98 degree angle are corresponding angles and m is parallel to n. dw I hate geometry too.

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2 years ago

The table shows whether a bus pass is a child's or an adult's pass and whether it is a daily or monthly pass. One bus pass is ra

OLEGan [10]

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3 years ago

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Determine whether the triangles shown can be

lidiya [134]

Answer:

not similar

Step-by-step explanation:

180-56-83=41

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2 years ago

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The distribution of weights of potato chip bags filled off a production line is unknown. However, the mean is m=13.35 OZs and th

Nikitich [7]

Answer:

a) $\mu_{\bar X} =13.35$

e.none of the above

b) $\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

a.0.0200

c) $z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

a.0.0668

d) $z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

c.0.6853

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(13.35,0.12)$

Where $\mu=13.35$ and $\sigma=0.12$

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

$\mu_{\bar X} =13.35$

Part b

$\sigma_{\bar X}= \frac{0.12}{\sqrt{36}}= 0.02$

Part c

We want this probability:

$P(\bar X< 13.32)$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.32-13.35}{\frac{0.12}{\sqrt{36}}}= -1.5$

$P(\bar X< 13.32)= P(z$

Part d

We want this probability:

$P(13.30$

For this case we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using this formula we got:

$z = \frac{13.30-13.35}{\frac{0.12}{\sqrt{36}}}= -2.5$

$z = \frac{13.36-13.35}{\frac{0.12}{\sqrt{36}}}= 0.5$

$P(13.30$

8 0

3 years ago