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Elden [556K]
3 years ago
15

What is 2+4×17÷3. Please help me

Mathematics
2 answers:
stepladder [879]3 years ago
5 0
2+4=6×17=102÷3=34 hope this help
solong [7]3 years ago
3 0
24.6667 

round it, it'll be 25
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Please help me there is a pic thankyou ​
shutvik [7]

Answer:

2

Step-by-step explanation:

y^m x y^n = y^m+n

so y^-4 x y⁶ = y^-4+6

-4+6=2

NOTE: ^ means to the power of

e.g: y^2 is y² :)

5 0
3 years ago
Read 2 more answers
Jose travels 130 miles in 150 minutes. How many miles does Jose travel in 1 hour? (Remember there are 60 minutes in 1 hour.)
Ganezh [65]

Answer:

55 miles

Step-by-step explanation:

x=the number of miles per hour

130(Miles)/150(minute)  =  x(Miles)/60(Minuet)

150x=2800

7800/150=52

7 0
3 years ago
You are helping your older sibling look for an apartment. There are 2 final choices. Apartment A is $1200 per month and requires
kogti [31]

Answer:

20 months.

Step-by-step explanation:

Let the number of months be represented as x

Apartment A is $1200 per month and requires a security deposit of $1000.

= $1200 × x + $1000

1200x + 1000

Apartment B is $1175 per month and requires a security deposit of $1500.

= $1175 × x +$1500

1175x + 1500

Apartment A = Apartment B

1200x + 1000 = 1175x + 1500

Collect like terms

1200x - 1175x = 1500 - 1000

= 25x = 500

x = 500/25

x = 20

Therefore, the costs for both apartment A and B will be the same after 20 months.

6 0
4 years ago
Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="
lyudmila [28]
We have point P=(x_0,y_0)=(2,-4), so first calculate f'(x_0). There will be:

y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}

Now, we can write the equation of the normal line as:

y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\&#10;0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}
8 0
3 years ago
For what value of k, if any, will y = ksin (5x) + 2cos (4x) be a solution to the differential equation y'' +16y =-27sin(5x)?
emmainna [20.7K]

Answer:

c. 3

Step-by-step explanation:

y = k sin(5x) + 2 cos(4x)

y' = 5k cos(5x) − 8 sin(4x)

y" = -25k sin(5x) − 32 cos(4x)

y'' + 16y = -27 sin(5x)

(-25k sin(5x) − 32 cos(4x)) + 16(k sin(5x) + 2 cos(4x)) = -27 sin(5x)

-25k sin(5x) − 32 cos(4x) + 16k sin(5x) + 32 cos(4x) = -27 sin(5x)

-9k sin(5x) = -27 sin(5x)

k = 3

4 0
4 years ago
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