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Gelneren [198K]
3 years ago
9

Freddy has a shelf that is 72/5 inches wide. How many catalogs can freddy arrange on the shelf if each catalog is 4/5 of an inch

thick?
Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer: 18 catalogs.

Step-by-step explanation:

(72 / 5) ÷ (4 / 5) =

(72 / 5) × (5/4) =

360 / 20 =

18

Hope this helped!  :)

Leni [432]3 years ago
4 0
Hey!

72/5 ÷ 4/5 

All you have to do is divide 72 by 4 because the denominator is the same.

72 ÷ 4 = 18

Answer ⇒ 18 catalogs

Hope this helps! :)
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vladimir2022 [97]
She will be paid $2,240.

The equation to use for this is: A=P(1+rt)

More specifically:
A = 2000(1 + (0.02 × 6)) = 2240
A = $2,240.00
5 0
3 years ago
A swimming pool is 22 feet long and 18 feet wide. How many feet of fencing are needed to enclose the pool
alexira [117]

Answer:

80 feet

Step-by-step explanation:

length of pool = 22    ,  width of pool = 18

feet required for fencing the pool = 2 (l +b)

= 2 ( 22+18)

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8 0
2 years ago
Read 2 more answers
Why is #2 the expression ln(2e)^3x equivalent to choice B?
motikmotik
Hello:
ln(2e^3x) =ln2+lne^3x
<span>                =ln2 +3xlne
                 = ln2+3x        .....lne=1       
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8 0
3 years ago
10. The surface area of a cylinder with radius rand height h is twice the product of r and the
rusak2 [61]

Step-by-step explanation:

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A=2\pi rh

or

A=2\pi \times r\times h

We also know that, surface area = perimeter×height

So, the surface area of the cylinder is the product of circumference of the circle and height of the cylinder.  

3 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
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