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rewona [7]
3 years ago
7

(Game Design) A number of elements in a specific order is:

Computers and Technology
2 answers:
mash [69]3 years ago
7 0

Yes the ansewer is c bc you can look it up!

mario62 [17]3 years ago
6 0

A union option C is correct.

Because union is a special data type that allows storing different data types in the same memory location.

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Counselors do NOT provide which service during treatment?
Ivan

Answer:

Civil settlement

Explanation:

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3 years ago
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Some email programs let you use a ____ to move incoming mail to a specific folder or to delete it automatically based on the con
KatRina [158]

Answer:

filter

Explanation:

Some email programs let you use a filter to move incoming mail to a specific folder or to delete it automatically based on the content of the message.​

The filter performs this role by either automatically deleting or moving to another location.

Most messages that are moved or deleted are unsolicited emails or spam messages.

Filtering of your mails helps so you ou can manage your incoming mail using filters to send email to a label, or archive, delete, star, or automatically forward your mail.

This is a way of organising your correspondence.

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3 years ago
When you use a mouse to select a row or column in a table, word displays a(n) ____?
Harrizon [31]
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3 years ago
The bank has a website that’s been attacked. The attacker utilized the login screen, and rather than entering proper login crede
RoseWind [281]

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7 0
3 years ago
let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest va
Ahat [919]

Answer:

Explanation:

From the given information:

a_{n-1} , a_{n-2}...a_o in binary is:

a_{n-1}\times 2^{n-1}  + a_{n-2}}\times 2^{n-2}+ ...+a_o

So, the largest number posses all a_{n-1} , a_{n-2}...a_o  nonzero, however, the smallest number has a_{n-2} , a_{n-3}...a_o all zero.

∴

The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times

i.e.

(11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}

= \dfrac{1(2^n-1)}{2-1}

\mathbf{=2^n -1}

(1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}

\mathbf {= 2 ^{n-1}}

Hence, the smallest value is \mathbf{2^{n-1}} and the largest value is \mathbf{2^{n}-1}

3 0
2 years ago
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