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3 years ago

Can someone help me ASAP??

Mathematics

1 answer:

ladessa [460]3 years ago

4 0

Yes ! What do you need help with

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(2) (x-7) (=3) (x+8)

Tasya [4]

Use the distributive property to get 2x - 14 = 3x + 24. Subtract 24 from both sides to get 2x - 38 = 3x. Subtract 2x from both sides to get -38 = x.

7 0

2 years ago

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What is the volume of a cone with diameter 21 m and height 4 m?

natima [27]

For this case we have by definition, that the volume of a cone is given by:

$V = \frac {1} {3} * \pi * r ^ 2 * h$

Where:

A: It is the cone radius

h: It's the height

They tell us that the diameter is 21 m, then the radius is half the diameter, that is: 10.5m. The height is 4m. Substituting the data:

$V = \frac {1} {3} * \pi * (10.5) ^ 2 * 4\\V = \frac {1} {3} * \pi * 110.25 * 4\\V = 147 \pi$ .

Finally, the volume of the cube is $147 \pi \ m ^ 3$

ANswer:

Option B

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2 years ago

Select the correct locations on the graph. select the lines that represent functions.<br>

sleet_krkn [62]

Answer:

right side, bottom. curve

Step-by-step explanation:

7 0

2 years ago

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What is a tenth of a decimal ?

trapecia [35]

One decimal place to the left decimal point is the place.

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3 years ago

Express p in terms of q if

Irina-Kira [14]

$p=x^2+\dfrac{1}{x^2}\\\\p=\dfrac{x^4}{x^2}+\dfrac{1}{x^2}\\\\p=\dfrac{x^4+1}{x^2}\qquad(*)$

$q=x+\dfrac{1}{x}\\\\q=\dfrac{x^2}{x}+\dfrac{1}{x}\\\\q=\dfrac{x^2+1}{x}\qquad\text{square both sides}\\\\q^2=\left(\dfrac{x^2+1}{x}\right)^2\\\\q^2=\dfrac{(x^2+1)^2}{x^2}\qquad\text{use}\ \ (a+b)^2=a^2+2ab+b^2\\\\q^2=\dfrac{(x^2)^2+2(x^2)(1)+1^2}{x^2}\\\\q^2=\dfrac{x^4+2x^2+1}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+\dfrac{2x^2}{x^2}\\\\q^2=\dfrac{x^4+1}{x^2}+2\qquad\text{subtract 2 from both sides}\\\\q^2-2=\dfrac{x^4+1}{x^2}\\\\\text{From (*) we have}\\\\\boxed{p=q^2-2}$

8 0

2 years ago