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3 years ago

Is this correct????? Please someone answer

Mathematics

1 answer:

Olegator [25]3 years ago

6 0

Answer:

48 is right!!

Step-by-step explanation:

the pattern is +10 +9 +8 +7 +6 +5 and so on

You might be interested in

If you triple 4 and subtract to each day how many days until you have zero

Mrrafil [7]

Do you mean subtract two each day? If so...
4x3=12 and 12 divided by 2 is 6 so it would take six days to reach zero
or
you could manually subtract two from 6 each days as in 12-2=10 (1 day), 10-2=8 (2 days), and so on...

5 0

3 years ago

YO PLS HELP IM STUCK!

lisov135 [29]

Answer:

thats what she said

Step-by-step explanation:

5 0

3 years ago

The table shows a linear function.

sergejj [24]

Answer:

$\large\boxed{y=\dfrac{5}{3}x+9}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the table we have an y-intercept (0, 9) → b = 9.

Take other point from the table (-6, -1).

Calculate the slope:

$m=\dfrac{-1-9}{-6-0}=\dfrac{-10}{-6}=\dfrac{5}{3}$

Finally:

$y=\dfrac{5}{3}x+9$

7 0

3 years ago

An airplane at T(80,20)needs to fly to both U(20,60) and V(110,85). what is the shortest possible distance for the trip?

olga2289 [7]

The answer is 165 units.

4 0

4 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

4 years ago