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Svetradugi [14.3K]
3 years ago
6

What is 5 pie compared to 15

Mathematics
1 answer:
Pie3 years ago
8 0
Since pi is about 3.14, and 3(5) is 15, 5(3.14) is bigger than 5(3).
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Which expression is equivalent to n + n - 0.18n?
horrorfan [7]

n + n - 0.18n

We can rewrite it as

2n - 0.18n

And if we solve it

(2 - 0.18)n = 1.82n

So the equivalente expression is B.

5 0
3 years ago
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Please solve and explain the question below
solong [7]

Answer:

OPTION A

Step-by-step explanation:

To find the table substitute the points on the given function and compare the values.

The given function is: $ y = x^2 + 2 $.

OPTION A:

(i) When x = -2

LHS = y = 6.

RHS = (-2)² + 2 = 4 + 2 = 6.

LHS = RHS

(ii) When x = -1

LHS = y = 3

RHS = (-1)² + 2 = 1 + 2 = 3.

LHS = RHS

(iii) When x = 0

LHS = y = 2

RHS = 0² + 2 = 2.

LHS = RHS

(iv) When x = 1

LHS = y = 3

RHS = (1)² + 2 = 1 + 2 = 3.

LHS = RHS

(v) When x = 2

LHS = y = 6

RHS = (2)² + 2 = 4 + 2 = 6

LHS = RHS

OPTION B:

(i) When x = -2

LHS = y = -2

RHS = (-2)² + 2 = 6

LHS \neq RHS

OPTION B is eliminated.

OPTION C:

(i) When x = -2

Using the same reason as OPTION B this option is eliminated as well.

So, OPTION A is the correct answer.

5 0
3 years ago
Please help me with this
Cerrena [4.2K]

Answer:

Yes;Each side of triangle PQR is the same length as the corresponding side of triangle STU

Step-by-step explanation:

You can observe  the sides of both triangles to see if this property holds

Lets check the length of AB

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AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\\\\\AB=\sqrt{(0-0)^2+(-1-3)^2} \\\\\\\\AB=\sqrt{0^2+-4^2} \\\\\\AB=\sqrt{16} =4units

Now check the length of the corresponding side DE

D(1,2)  and E(1,-2)

DE=\sqrt{(1-1)^2+(-2-2)^2} \\\\\\DE=\sqrt{0^2+-4^2} \\\\\\DE=\sqrt{16} =4units

The side AB has the same length as side DE.This is also true for the remaining corresponding sides.

6 0
4 years ago
Graph (y=-2x+5)<br><br> Plz have it answered in 5 min.<br> It is on Khan Academy
8_murik_8 [283]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
When a principal amount, P, is invested at an annual interest rate,r, and compounded n times per
romanna [79]

Answer:

2

Step-by-step explanation:

A = P( 1+r/n) ^ (nt)

P is the amount invested

r is the rate

n is the number of times per year the interest is compounded

t is the number of years

every 6 months is twice a year

so n is 2

8 0
3 years ago
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