Answer:
Step-by-step explanation:
a3+b3+c3-3abc
Hint: a3+b3 = (a+b)3 -3ab(a+b)
(a+b)3 - 3ab(a+b) +c3 - 3abc
(a+b)3 + c3 -3ab(a+b) - 3abc
(a+b+c)3 - 3(a+b)c(a+b+c) -3ab(a + b + c)
(a+b+c)3- 3(a + b + c)[(a+b)c+ab]
(a+b+c)3 - 3(a + b + c)[(a+b)c+ab]
(a+b+c)[(a+b+c)2 -3(ab + ac + bc)]
(a+b+c)[a2 +2ab + b2 +2ac + 2bc + c2 - 3ab - 3ac- 3bc]
(a + b + c)(a2 + b2 + c2 - ab - ac- bc)
