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sveticcg [70]
3 years ago
8

. In a study about the relationship between the age of a person and the preference for digital vs analog watches, which of the f

ollowing could be valid data sets? (Choose all that apply) A.height of a person B.watch preference for those who are less than 30 years C.the quality of the strap of the watch D.type of watch, digital or analog D.age of a person
Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

B and the first d and second one.

Step-by-step explanation:

The age is a big factor and b can showing the preference per age

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Which is the greater rate of change? <br><br> -1/2<br><br> 4/1
mote1985 [20]
4/1 is a greater rate of change because it is the same as 4. A whole number will always be greater than a fraction and also the fraction is negative which makes it even smaller than a regular fraction. I hope this answers your question! :)
3 0
3 years ago
Find a numerical value of one trigonometric function of x for cscx=sinxtanx+cosx
ehidna [41]

cscx = sinx tan x + cos x

Using xsx x = 1/sin x and tan x = sin x/cos x

\frac{1}{sin x} = sinx *\frac{sinx }{cos x} + cosx

\frac{1}{sin x} = \frac{sin^2x +cos^2x}{cos x}

\frac{1}{sin x} = \frac{1}{cos x}

Multiplying both sides by cos x

\frac{cos x}{sin x} = 1

cot x =1

Correct option is d .

5 0
3 years ago
Read 2 more answers
7/7q+21= x /5q^2-45 then x=?​
anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

3 0
2 years ago
Jimmy has a window frame in his house. The window measures to have a width of 36 inches and a height of 48 inches. What is the d
Olenka [21]

Answer:

B.60 inches

Step-by-step explanation:

you know you can consider two triangles because of the diagonal cut. and the distance wound be √(36²+48²)=60 inches

4 0
2 years ago
Need brief explanation about why false is correct
anyanavicka [17]

<u>We are given the equation:</u>

(a + b)! = a! + b!

<u>Testing the given equation</u>

In order to test it, we will let: a = 2 and b = 3

So, we can rewrite the equation as:

(2+3)! = 2! + 3!

5! = 2! + 3!

<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>

120 = 2 + 6

We can see that LHS ≠ RHS,

So, we can say that the given equation is incorrect

6 0
2 years ago
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