Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
Answer:
- 0.9503 ; r is not statistically significant ; 0.9031
Step-by-step explanation:
Given the following :
Age (X) :
37
41
57
65
73
Bone density (Y)
355
345
340
315
310
Using the pearson R value calculator :
The r value of the data % - 0.9503.
This value depicts a very strong negative correlation between age and density of bone.
Using the pearson R calculator to obtain the P- value, the P value obtained is .01332 and hence the r is not significant at P < 0.01.
The Coefficient of determination R^2 can be obtained by getting the square value of R
R^2 = - 0.9503^2
R^2 = 0.90307009
R^2 = 0.9031
Answer:
Step-by-step explanation:
Additive inverse of (5a² - 4a + 3) should be added to make them zero
(5a² - 4a + 3) + (-5a² + 4a - 3)= <u>5a² - 5a² </u> <u>- 4a + 4a</u> <u>+ 3 - 3</u>
= 0
Answer:
Step-by-step explanation:
51.78 is rounded up to 52
Answer:
#1
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