Question

Please help will vote brainliest

Answer 1

Answer:

D

Step-by-step explanation:

Start by factoring out each radical.

$\sqrt{16x^{3}} = \sqrt{16}*\sqrt{x^{3}} = 4\sqrt{x^{3}}$

$\sqrt{8x} = \sqrt{4} * \sqrt{2x} = 2\sqrt{2x}$

Add them to get:

$\frac{4\sqrt{x^{3}}}{2\sqrt{2x}} = \frac{4\sqrt{x}\sqrt{x}\sqrt{x}}{2\sqrt{2}\sqrt{x}} = \frac{4\sqrt{x}\sqrt{x}}{2\sqrt{2}} = \frac{2x^{2}}{\sqrt{2}} = \sqrt{2} x^{2}$

D is the answer