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3 years ago

NEED HELP ASAP

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

5 0

Photo math works and the answer would be on that app!!

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I NEED THIS REALLY QUICK ILL GIVE BRAINLIEST AND 5 STARS PLEASE AWNSER

Elan Coil [88]

The answers is 14 if you follow the equation i just did it on a calculator (attached)

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3 years ago

Read 2 more answers

What is the product of 41 and 8.4 x 10^4 expressed in scientific notation?

LenaWriter [7]

Answer:

3.44 x 10^6

Step-by-step explanation:

41 x 8.4 = 344.4

344.4 x 10^4 = 3.44 x 10^4+2

6 0

3 years ago

Guys I need help will mark brainliest

omeli [17]

Answer:

mean= sum of the terms/ (over) number of terms

4 0

3 years ago

WHAT DEFINES THE SOLUTION SET FOR THE INEQUALITY -X/2 +4<12 ? DUE BY 10:50

Marrrta [24]

-x/2+4<12

-4 -4

-x/2<8

*2 *2

-x<16

/-1 /-1

x<-16

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hope it helps

4 0

2 years ago

The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9

mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0

3 years ago