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s344n2d4d5 [400]
3 years ago
12

WILL MARK BRAINLIEST!!!!Which of the following relations is not a function?

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

The third (C) option is the answer.

Because 4 is repeating in x coordinate,

that is called <u>D</u><u>o</u><u>m</u><u>a</u><u>i</u><u>n</u>.

It's allowed to be repeated in y coordinates,

that is called <u>R</u><u>a</u><u>n</u><u>g</u><u>e</u><u>.</u>

Good luck!

Intelligent Muslim,

From Uzbekistan.

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A function which has a constant difference per interval is?
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Answer:

I think A or C I'm not sure tho

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3 years ago
Which of the following is the mathematical representation of Boyle's law?
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The mathematical representation of Boyle's law is P1V1 = P2V2. The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.
3 0
3 years ago
Help with this question
Sholpan [36]

With some simplification,

cos⁻¹(x) - 5 cos⁻¹(x) - π/3 = 2π/3

becomes

-4 cos⁻¹(x) = π

or

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However, the inverse cosine function has a range of 0 ≤ cos⁻¹(x) ≤ π, so there are no solutions to this equation.

4 0
3 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
3 years ago
Please help<br><br><br><br> Thank yoy
BabaBlast [244]

Answer:

I think its graph 4

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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