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3 years ago

WILL MARK BRAINLIEST!!!!Which of the following relations is not a function?

Mathematics

1 answer:

Inessa [10]3 years ago

3 0

Answer:

The third (C) option is the answer.

Because 4 is repeating in x coordinate,

that is called Domain.

It's allowed to be repeated in y coordinates,

that is called Range.

Good luck!

Intelligent Muslim,

From Uzbekistan.

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A counter top is 18 feet long and 3 feet wide. What is the area of the counter top in square meters? Use the conversion 1 foot =

podryga [215]

Answer:

Area of the counter top is $5.02\ m^2$ .

Step-by-step explanation:

Given:

Length of the Counter top = 18 feet

Width of the counter top = 3 feet

We need to find the area of the counter top is square meter;

Solution:

Now we need to find the area of the counter top is square meter.

But given data is in feet so we will first convert feet into meters.

1 foot = 0.305 meter.

So 18 feet = Number of meters in 18 feet.

By Using Unitary method we get;

Number of meters in 18 feet = $18\times 0.305 = 5.49\ m$

Length of the Counter top = 5.49 m

Also 3 feet = Number of meters in 3 feet.

Again Using Unitary method we get;

Number of meters in 3 feet = $3\times 0.305 = 0.915\ m$

Width of the counter top = 0.915 m

Now we know that;

Area of the counter top can be calculated by multiplying Length of the counter top with width of the counter top.

framing in equation form we get;

Area of the counter top = $5.49\times 0.915 = 5.0233\ m^2$

Rounding up to 2 decimals we get;

Area of the counter top = $5.02\ m^2$

Hence Area of the counter top is $5.02\ m^2$ .

3 0

3 years ago

Find 601st term of the arithmetic sequence whose first term is -85 and the common difference is 1/6.

irakobra [83]

Answer:

Step-by-step explanation:

Arithmetic sequence

Tn = a+(n-1)d

= -85 +(601-1) 1/6

= -85 + 600/6

= -85 + 100

= 15

601th term is 15

8 0

3 years ago

11 + 11 = 4 22 + 22 = 16 33 + 33 = ?

Anon25 [30]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1. There are 51 families in Oakville who have

marishachu [46]

Answer: 17 families

Step-by-step explanation:

3 0

2 years ago

Would appreciate some help with this: Verify (sinq+cosq)^2 - 1 = sin2q

Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq (*)

Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb

sin(2q) = (**)

sinq*cosq + cosq*sinq => as both terms are identical

2 sinq*cosq

Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)

= 1 + sin(2q)

Hence

(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides

(sinq + cosq)^2 - 1 = sin(2q)

The last statement is what we are trying to prove.

Thank you,

MrB

7 0

3 years ago