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mote1985 [20]
3 years ago
6

Rewrite 30+42 using distributive property

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0
<h2>5(2+4) + 2(10+11)</h2><h2>10+20     20+22</h2><h2>30           42</h2>
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Find the surface area
zalisa [80]

Answer:

72

Step-by-step explanation:

15 + 15 + 12 + 12 + 18 gives you 72 you add all the areas

6 0
3 years ago
Is (x - 1) a factor of P(x) = 4x? - 9x2 + 4x+1? If it is, write P(x) as a product of
trasher [3.6K]

Answer: i don't even know what a factor is

Step-by-step explanation:

8 0
3 years ago
(06.04)
otez555 [7]

Answer:

5x/3y2

Step-by-step explanation:

8 0
3 years ago
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consider the line y= 2/3x-0. Find the equation of the line that is parallel to this line and passes through the point (8, 4).
tresset_1 [31]
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)

slope intercept form :
y=m+b

m=slope

If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.

Data:
(8,4)
m=2/3

y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3  (slope intercept form)

Answer: The equation of the line would be: y=2/3 x-4/3.


if we have the next slope "m",then the perendicular slope will be:
m´=-1/m

We have this equation: y=2/3 x+0; the slope is: m=2/3.

The perpendicular slope will be: m`=-1/(2/3)=-3/2

And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:

y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16

answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
3 0
3 years ago
Objects A and B are in harmonic motion modeled by
Zepler [3.9K]

Answer:

The phase difference between yA and yB is  \frac{-\pi }{12}

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t  - \frac{\pi }{3})         And

yB = 8 sin(2t  - \frac{\pi }{4})

The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  \frac{\pi }{3} + \frac{\pi }{4} )

Or, phase difference between yA   and  yB = (\frac{-4\pi +3\pi }{12})

I.e phase difference between yA   and  yB =\frac{-\pi }{12}

Hence The phase difference between yA and yB is \frac{-\pi }{12}   Answer

4 0
4 years ago
Read 2 more answers
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