Question

Solve x2 + 4x – 4 = 8 for x.

Answer 1

we know that

To find the solution let's factor the equation

$x^{2} + 4x - 4 = 8$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} + 4x = 8+4$

$x^{2} + 4x = 12$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} + 4x+4 = 12+4$

$x^{2} + 4x+4 = 16$

Rewrite as perfect squares

$(x+2)^{2} = 16$

$(x+2)^{2} = 16\\ (x+2)=(+/-)\sqrt{16} \\ x1=-2+\sqrt{16} =-2+4=2\\ x2=-2-\sqrt{16} =-2-4=-6$

therefore

the answer is the option

A. –6 or x = 2

Answer 2

A. x=-6 or x=2
Quadratic equation