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azamat
3 years ago
8

Solve x2 + 4x – 4 = 8 for x.

Mathematics
2 answers:
DochEvi [55]3 years ago
5 0

we know that

To find the solution let's factor the equation

x^{2} + 4x - 4 = 8

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2} + 4x = 8+4

x^{2} + 4x = 12

Complete the square. Remember to balance the equation by adding the same constants to each side

x^{2} + 4x+4 = 12+4

x^{2} + 4x+4 = 16

Rewrite as perfect squares

(x+2)^{2} = 16

(x+2)^{2} = 16\\ (x+2)=(+/-)\sqrt{16} \\ x1=-2+\sqrt{16} =-2+4=2\\ x2=-2-\sqrt{16} =-2-4=-6

therefore

the answer is the option

A. –6 or x = 2


jok3333 [9.3K]3 years ago
5 0
A. x=-6 or x=2
Quadratic equation
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Step-by-step explanation:

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400 pounds per 340 square feet” as a rate in simplest form
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400lbs/340ft^2

Factor out largest common factor.  LCF is the product of shared primes of the numbers prime factorization.

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4 0
3 years ago
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3 0
3 years ago
Read 2 more answers
at 10a.m. you consume an energy drink containing 800mg of caffeine. if the half-life of caffeine is 5.7 hours, how much caffeine
icang [17]

Answer:

268 mg

Step-by-step explanation:

Let A₀ = the original amount of caffeine

The amount remaining after one half-life is ½A₀.

After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.

After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.

We can write a general formula for the amount remaining:

A =A₀(½)ⁿ

where n is the number of half-lives .

n = t/t_½

Data:

  A₀ = 800 mg

    t₁ = 10 a.m.

   t₂ = 7 p.m.  

t_½ = 5.7 h

Calculations:

(a) Calculate t

t = t₂ - t₁ = 7 p.m. - 10 a.m. = 19:00 - 10:00 = 9:00 = 9.00 h

(b) Calculate n

n = 9.00/5.7 = 1.58

(b) Calculate A

A = 800 × (½)^1.58 = 800 × 0.334 = 268 mg

You will still have 268 mg of caffeine in your body at 10 p.m.

6 0
3 years ago
Can someone help with this?
skelet666 [1.2K]

Answer:

A

Step-by-step explanation:

only Ali's way would work in this situation. since there is a 5 on the right side, you can not use the zero product property. this only works if the right side is 0. so, you must use Ali's method.

6 0
3 years ago
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