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3 years ago

A university is composed of five schools. The enrollment in each school is given:

Mathematics

1 answer:

Lostsunrise [7]3 years ago

8 0

Answer:

34.767 enrollments/computer

Step-by-step explanation:

According to the Hamilton's method, the standard divisor, D, is determined by dividing the number of enrollments in all schools by the number of new computers available:

$D=\frac{1050+1410+1850+2540+3580}{300}\\D=34.767\ enrollments/computer$

The standard divisor for this situation should be 34.767 enrollments/computer.

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Luke has $21 more than rachel and $48 more than daniel. altogether they have $168. how much does luke have?

Anettt [7]

this can be solve by 3 variable equation

let x be the money of luke

y money of rachel

z money of daniel

first equation

x = y + 21

second equation

x = z + 48

third equation

x + y + z = 168

solving simultaneously

x =79

y = 58

z = 31

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after working out for just 8 minutes,ron has burned 56 calories. how many minutes must he work out if he wants to burn 392 calor

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Sanja made a hole-in-one on the sixth hole of miniature golf 8 times and missed it 4 times. If Sanja attempts 24 more holes-in-o

hram777 [196]

Answer:

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Step-by-step explanation:

I just did the guiz and got that one right

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3 years ago

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A company has 50 employees all working in the same building.

balandron [24]

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2 years ago

The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

GIVEN :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

TO FIND :

in the provided question we need to find :

➠ Radius of cylinder
➠ Diameter of cylinder

$\begin{gathered}\end{gathered}$

USING FORMULAS :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

$\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}$

➛ Csa = Curved surface area
➛ π = 22/7
➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

SOLUTION :

Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$

Hence, the diameter of the base of the cylinder is 2 cm.

$\rule{300}{2.5}$

3 0

2 years ago

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