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Virty [35]
3 years ago
12

8/6 = x + 2/32Solve for X Show work and answer can't be put into decimal form

Mathematics
1 answer:
yuradex [85]3 years ago
5 0
<span>8/6 = x + 2/32

To solve this, you need to subtract 2/32 from both sides. To do that though, the two fractions need to have a common denominator.

2/32 can be simplified to 1/16.

The lowest denominator they have in common is 48.
1/16 = 3/48
8/6 = 64/48

Now subtract them.
</span>(64/48) - (3/48) = 61/48

That cannot be simplified, so it's the final answer.
x = 61/48
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Answer:

True, False, False, False

Step-by-step explanation:

I'll find the lengths of all sides of the drawing before answering individual answers so that it's less confusing.

1) The question says that QR is a perpendicular bisector of TS. This means that the length of TQ and QS is the same. Also, since both triangles TRQ and SRQ share the same side RQ, and the angle between the two segments is 90 degrees, the two triangles are congruent (RTQ and RSQ) using SAS.

2) Side RT and TS will have the same length since the two triangles are congruent. (2x+1) = (4x-3) --> -2x = -4 --> x = 2. We can conclude that x = 2.

3) Now that we know that x = 2, we can find the length of side RS by replacing the x with 2. 4(2)-3 is 5, so RS = 5.

4) We can use the Pythagorean theorem to find RQ (Hypotenuse^2 = Other two sides added after being squared individually). Since the hypotenuse of triangle RSQ is RS which is 5, and one side is 4, we can input those into our equation. (5)^2 = (4)^2 + (RQ)^2. --> 25 = 16 + (RQ)^2 --> 9 = (RQ)^2 --> RQ = 3.

5) Since the two triangles RTQ and RSQ are congruent, side TQ and SQ also have the same length, since CPCTC (Corresponding parts of congruent triangles are congruent). QS is 4, so TQ will also be 4. This means that ST will be 8 (4+4). ST = 8

Now that we have all the clues, all we need to do is choose True or False.

RS = 5 is TRUE

RS = 4 is FALSE

ST = 10 is FALSE

QR = 4 is FALSE

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We have numerators A and B added together over a common denominator C. If we didn't have a common denominator, then we'd have to do a bit of algebraic manipulation to get both fractions to a common denominator. It doesn't have to be the lowest common denominator (LCD), though it's often more efficient that way.

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