12%=(3+10%*x)/(20+x)
x=30
add 30 pounds of the second alloy
Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
9. x=102
10. x=56
11. x=104
12. x=138
Step-by-step explanation:
9. In this problem, they are alternate exterior angles, meaning they are the same value. x=102
10. x is a corresponding angle, meaning they are the same. x=56
11. There are consecutive interior angles. The sum of these two angles is 180. to find x, subtract 76 from 180. 180-76 = 104 x = 104
12. These two angles are verticle angles, meaning they are equivalent. x = 138
The answer is 17! Hope it helps :)
