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aksik [14]
4 years ago
12

The lengths of the diagonal of the rhombus are given. What is the area of the rhombus. HELP Now!! Lengths of diagonals(23 in and

28 in)
Mathematics
1 answer:
olga nikolaevna [1]4 years ago
3 0
Consider, pls, this option:
1. note, that area_of_rombus=0.5*diagonal_1*diagonal_2.
2. according to the formula above:
area=0.5*28*23=14*23=322 (inch²).

answer: 322 in².
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A.4<br> B.3<br> C.2<br> D.1<br><br> Help please
vazorg [7]
The number of exports is GREATER than the number of imports if the bar for exports (pink) is TALLER than the bar for imports (blue).  It appears that happens only on Friday.
3 0
3 years ago
One third of the difference of 20 and 2 <br> 1/3 x (20-2)
Alchen [17]
ANSWER:
6

Explanation:
20-2 = 18
1/3 = 0.33333 (3 repeating)
1/3 x 18 = 6
4 0
3 years ago
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
How many counterexamples does it take to show that a conditonal statement is false?
iren [92.7K]

<u>Answer:</u>

<u>one</u>

<u>Explanation:</u>

First, note that a conditional statement in mathematics refers to a statement in which a hypothesis is given followed by a conclusion. Such as saying if P then "Q”, P  and Q  are sentences.

For example, a good example of conditional statement;

"If today is Sunday,<u> then tomorrow is Monday"</u>(hypothesis not underlined; condition underlined). While the counterexample could be one example or statement that satisfies the condition(s) of the statement but does not satisfy the conclusion.

5 0
3 years ago
Whats v=( 3.14)(11)2(6)
ElenaW [278]
<span>Whats v=( 3.14)(11)2(6)?
I'd suggest using a calculator.  You could enter these numbers in any order. 

Please note that 11^2 denotes "the square of 11," which is 121.
Pleasure be certain to write that as 11^2, and not as (11)2.

</span><span>Whats v=( 3.14)(11)^2(6)?  3.14(121)(6) = 2279.64</span>
7 0
4 years ago
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