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nordsb [41]
3 years ago
13

Which of the following scatter plots shows a strong, negative linear association between variables ?

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

A

Step-by-step explanation:

The dots are all along the line, which makes it strong, and the line is going down, which makes it negative.

hope this helps :)

Ivan3 years ago
4 0

Answer:

A is the answer.

Step-by-step explanation:

All of the points are together and the line is going down. PLEASE MARK BRAINLIEST!!!!!!!!!!

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What is 2/3x2/5pls I need an answer fast sorry I suck at math
wlad13 [49]

Answer:

4 /1 5 also 0.26666666666

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8 0
2 years ago
Which of the following is a solution of y - x &gt; -3? <br> (6, 2)<br><br> (2, 6)<br><br> (2, -1)
Margarita [4]
(2, 6)
x = 2 
y = 6
 y - x > -3
6 - 2 > -3
4 > -3
Therefore the answer is (2, 6)
6 0
3 years ago
Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what should the in
Korvikt [17]
<span>x-axis: hours in increments of 1; y-axis: miles in increments of 5

You always want the constant numbers such as time on the x-axis
And since your y values are all large numbers and multiples of 5, it makes sense to use increments of 5</span>
6 0
3 years ago
What is the awnser to 5+(5x20)x 30
katovenus [111]

Answer: 3005

Step-by-step explanation: multiply 5 by 20 and it will give 100 then times 30 Equals 3000 and plus gives 3005 . Please mark brainliest

6 0
2 years ago
Read 2 more answers
Pls help quick will put brainliest
Olin [163]

Answer:

m<SQP=124°

Step-by-step explanation:

Hi there!

We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)

we need to find m<SQP (given as x+72°)

exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).

that means that m<SQP=m<R+m<S (Exterior angle theorem)

substitute the known values into the equation

x+72°=90°+34° (substitution)

combine like terms on both sides

x+72°=124° (algebra)

subtract 72 from both sides

x=52° (algebra)

however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP

m<SQP=x+72°=52°+72°=124° (substitution, algebra)

Hope this helps!

4 0
3 years ago
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