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lana66690 [7]
2 years ago
15

What is the exact value of sin(165°)?

Mathematics
1 answer:
vodomira [7]2 years ago
6 0

here's something i found online, hope it helps

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What ia the angle of AOC and DOE
natulia [17]

(i) Angle AOC would equal 48°, as it is vertically opposite to angle DOB and they are therefore equal.


(ii) Angle DOE would equal 42°. We can see this because angles on a straight line add up to 180°, and 90 + 48 = 138, so we can do 180 - 138 = 42°.


I hope this helps!

4 0
3 years ago
I’m confused on this one
Lorico [155]
The question is asking which of the following does not have side that are parallel. So which of them have lines that would never touch if they were never ending lines.
4 0
3 years ago
PLEASE HELP ME.........
earnstyle [38]

Answer:

254.5

Step-by-step explanation:

5 0
3 years ago
Factorize <br><img src="https://tex.z-dn.net/?f=a%20%7B%7D%5E%7B2%7D%20%20-%209b%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="
lakkis [162]

Answer:

(a - 3b)(a + 3b)

Step-by-step explanation:

a² - 9b²

(a)² - (3b)²

(a - 3b)(a + 3b)

3 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points (0, -4) and (-4, 6)?
olganol [36]

Answer:

The equation of the line is.

y=-\frac{5}{2}x-4

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points (x_{1},y_{1}) and (x_{2},y_{2}) is.

\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}

\frac{x}{-4}=\frac{y+4}{6+4}

-\frac{x}{4}=\frac{y+4}{10}

-\frac{10x}{4}=y+4

-10x=4(y+4)

-10x=4y+16

4y=-10x-16

The above equation is divided by 2 both sides.

2y=-5x-8

y=-\frac{5}{2}x-4

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is y=-\frac{5}{2}x-4

8 0
2 years ago
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