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Vlad1618 [11]
3 years ago
10

−3x + 7y = −16 −9x + 5y = 16 slove this

Mathematics
1 answer:
Ahat [919]3 years ago
5 0


{-3x+7y=-16 ⇒ -3x=-16-7y    (↓)

{-9x+5y=16

The second equation:

-9x+5y=16

3*(-3x)+5y=16         <em>Substitute -3x    (↑)</em>

<em>3* </em>(-16-7y)+5y=16

-48-21y+5y=16      /+48

-16y=64      /:(-16)

y=-4

-3x=-16-7y

-3x=-16-7*(-4)=-16+28=12

-3x=12    /:(-3)

x=-4

<em /><em>Solution: (-4; -4)</em>



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m= -3/2

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3 years ago
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a large container holds 5 gallons of water. it begins leaking at a constant rate. after 15 minutes, the container has 2 gallons
Scrat [10]

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8 0
3 years ago
How much money has to be invested at 5.9% interest compounded continuously to have $15,000 after 12 years?
scoray [572]

The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.

Step-by-step explanation:

The given is,

                Future value, F  = $15,000

                           Interest, i = 5.9%

              ( compounded continuously )

                            Period, t = 12 years

Step:1

           Formula to calculate the present with compounded continuously,

                                       F=Pe^{(i)(t)}...............(1)

           Substitute the values in equation (1) to find the P value,

                                  15000=Pe^{(0.059)(12)}          ( ∵ i = \frac{5.9}{100}=0.059 )

                                  15000=Pe^{0.708}

                                  15000=P(2.0299)             ( ∵ e^{o.708} =2.0299 )

            We change the P (Present value) into the left side,

                                        P=\frac{15000}{2.0299}

                                            =7389.427

                                            ≅ 7389.43

                                         P = $ 7389.43

Result:

           The amount of $7389.43 has to be invested at 5.9% interested continuously to have $15,000 after 12 years.  

                       

8 0
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substitute L in equation for area

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a = 2; b = 2.5; c = 62.5

send a comment if you have a question

7 0
3 years ago
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