Factor the trinomial!! PLEASE HELP and if possible please explain how to do this!!
1 answer:
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Hi there!
Answer:
length = 9 kilometres
Width = 12 kilometres
Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.
Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.
The area of a rectangle can be found by using the formula:
A = width × length
Plug in the data from the formula
A = x (2x - 6).
Simplify using rainbow technique.
Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.
Subtract 108
Divide by 2.
Rule AB = 0, gives A is 0 or B is 0.
The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).
Length
Width
Answer:
length = 9 kilometres
Width = 12 kilometres
~ Hope this helps you!
Answer:
length = 9 kilometres
Width = 12 kilometres
Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.
Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.
The area of a rectangle can be found by using the formula:
A = width × length
Plug in the data from the formula
A = x (2x - 6).
Simplify using rainbow technique.
Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.
Subtract 108
Divide by 2.
Rule AB = 0, gives A is 0 or B is 0.
The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).
Length
Width
Answer:
length = 9 kilometres
Width = 12 kilometres
~ Hope this helps you!
Answer:
The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.
Step-by-step explanation:
Using Bayes' Theorem
P(A|B) =
where
P(B|A) is probability of event B given event A
P(B|a) is probability of event B not given event A
and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.
For this problem,
Let P(B1) = Probability of machine B1 = 0.3
P(B2) = Probability of machine B2 = 0.2
P(B3) = Probability of machine B3 = 0.5
Let P(D) = Probability of a defective product
P(N) = Probability of a Non-defective product
P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003
P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006
P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010
Likewise,
P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997
P(N|B2) be probability of a non-defective product produced by machine 2 = 1 - P(D|B2) = 1 - 0.006 = 0.994
P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990
For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)
P(B1|N) = =
= 0.1138
Hence the probability that a non-defective product is produced by machine B1 is 11.38%.