Question

Maria has added 2 liters of pure water to 8 liters of a 48% sugar syrup. What is the concentration of the resulting solution?

Answer 1

C1V1 = C2V2
0.48×8L = C2(10L)
C2 = (3.84)/10 = 0.384 = 38.4% sugar

Answer 2

$\\ \text{Let the concentration of the resulting solution be x}.\\ \text{Maria has added 2 liters of pure water to 8 liters of a }48\% \text{ sugar syrup.}\\ \\ \text{so the total solution would become}=2 \text{ liters+8 liters}=10\text{ liters}\\ \\ \text{so we have}\\ \\ 2\times (0 \% \text{ suger syrup})+8\times (48\% \text{ suger syrup})=10\times (x \% \text{ suger syrup})\\ \\ \Rightarrow 0+8\times (0.48)=10x\\ \\ \Rightarrow 3.84=10x\\ \\ \Rightarrow x=\frac{3.84}{10}\\ \\ \Rightarrow x=0.384$

Hence the concentration of the resulting solution is 38.4 %