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s344n2d4d5 [400]
3 years ago
13

How do you simplify this

Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0
It's 2/5 in decimal form it is 0.4.
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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
mars1129 [50]
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
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the sum of a geometric seequence is
S_{n}=\frac{a_{1}(1-r^{n})}{1-r}
a1=1
r=2
we want to find S_{10} (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

S_{10}=\frac{1(1-2^{10})}{1-2}
S_{10}=\frac{(1-1024}{-1}
S_{10}=\frac{(-1023}{-1}
S_{10}=1023

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3 years ago
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Anna35 [415]

Answer:

300

Step-by-step explanation:

50 and above is rounded up

49 and below is rounded down

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Step-by-step explanation:

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