Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
－81＝3(5－4r)
27＝－(5－4r)
27＝－5＋4r
－4r＝－5－27
－4r＝－32
r＝8
Hope my answer helped u :)
I think it’s 3885
Because 6216 divided by 8 is 777, 777x5 is 3885.
I hope that’s right and answers your question
Answer:
n = - 10
Step-by-step explanation:
10(-3n + 8) = 380
-30n + 80 = 380
80 - 380 = 30n
30n = - 300
n = - 300 : 30
n = - 10
He literally or she sorry by the way but they said clearly no links they should kick people with that
