Let x = number of lines
x/3 = r2 2,5,8,11,14,17,20,23,26,29,32,35,38,41,44,47
x/5 = r2 2,7,12,17,22,27,32,37,42,47
x/7 = r5 5,12,19,26,33,40,47
47 is the smallest number that fits all 3 requirements.
Answer:
The question is not complete.
Step-by-step explanation:
Answer:
1236 sq. m
explanation:
Side of square field = 100m
Area of the square field = side * side
= 100 * 100
= 10,000 sq. m
A path of 3m wide is built outside and along the boundary.
Side of path = 100(from the side of field) + 3(from the upper side) + 3(from below)
= 100 + 6
= 106 metres.
Area of the along with whole square path with side 106m = side * side
= 106 * 106
= 11,236sq.m
Now, Area of whole square = Areas of square field + area of path
therefore, Area of the path only = 11,236 - 10,000
= 1,236sq.m
If that is saying 390m tall, cm is a unit of meters, KHDMDCM, so the building is 39,000cm tall. Divide 39,000cm by 30cm, you end up with 1,300 feet. The answer is 1,300 feet
so hmm check the picture below, thus the ball hits 19 feet of height twice, once on the way up, and once on the way down, at about 0.64 seconds and at 1.17 seconds.