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Ber [7]
3 years ago
15

What 3 digits are in the thousands period for this number 9,827,276

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0
The thousands are 827 after nine
You might be interested in
Which ordered pair in the form (X,Y) solution to this equation (x+y)y=10
Verizon [17]

Answer:

X=3

Y=2

Step-by-step explanation:

(3+2)2=10

If you use this, please give me brainliest

3 0
4 years ago
What is 2.4 x 1.5 = please please help also please show work
Katena32 [7]
That’s easy just place 2.4 on top of 1.5 and do the math, I did it in the picture for you, since there are two decimal points one in 2.4 and the second in 1.5. So the answer is 3.60 as shown in the pic. Any questions ? Sorry the picture is sort of messed

5 0
4 years ago
A frequency table for the 30 best lifetime baseball batting averages of all time is shown to the right. These data can be graphi
Mashcka [7]

Answer: B

Step-by-step explanation:

Histogram is a statistical graph with the use of bar. The bar are not seperated unlike bar chart.

0.320 to 0.329 and 0.360 to 0.369 are of the same frequency which is equal to one. 0.350 to 0.359 is of frequency 2 a little above frequency 1.

Option B and D are very close to each other in value representation. But the frequency of 0.350 to 0.359 in option D is 3. This renders option D invalid and make option B the correct answer.

5 0
4 years ago
Using elimination (add or sub) find the solution to the following system of equations 5x+ 3y=9 2x -3y=5
Levart [38]
5x+3y=9
2x-3y=5

5x+2x=9+5
7x=14
14/7x= 2
x=2

sub it in so you get y

5(2)+3y=9
10+3y=9 (-10 to get rid of it)
3y=-1
3y/-1= - 1/3

x= 2 y= - 1/3
8 0
3 years ago
Simplify the expressions.<br> i^23
masha68 [24]

Answer:

-i

Step-by-step explanation:

i^0=1

i^1=i

i^2=-1

i^3=-i

i^4=1

This repeats so we want to see how many 4 factors of i there is in i^(23) which is 5 with a remainder of 3.

So i^(23)=i^3=-i.

i^(23)=i^(5*4+3)=(i^4)^5 * (i^3)=(1)^5 * (-i)=1(-i)=-i.

8 0
3 years ago
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