Step-by-step explanation:
Volume =pir^h
V1=pi r1^h
V2=pir2^2h
Now,V1/V2=r1^2/r2^2
v1/v2=r1^2/(1.05)^2 ((r2=r1+5/100r1)
v1/v2=1/1.1025
v1/v2=0.907
(v1/v2-1)=0.0907×100%
(v1-v2)/v2=9.07%
increase in volume is 9.07%
Answer:
a) The half life of the substance is 22.76 years.
b) 5.34 years for the sample to decay to 85% of its original amount
Step-by-step explanation:
The amount of the radioactive substance after t years is modeled by the following equation:
In which P(0) is the initial amount and r is the decay rate.
A sample of a radioactive substance decayed to 97% of its original amount after a year.
This means that:
Then
So
(a) What is the half-life of the substance?
This is t for which P(t) = 0.5P(0). So
The half life of the substance is 22.76 years.
(b) How long would it take the sample to decay to 85% of its original amount?
This is t for which P(t) = 0.85P(0). So
5.34 years for the sample to decay to 85% of its original amount
Answer:
Step-by-step explanation:
See attachment
12. -23C
13. 28.9% Loss
14. Diagram in the attachment. The sides can be calculated with the Pythagorean Theorem. Side = 3.61 cm
15. Use trig relationships. x = 5, y = 8.66
Answer:
17C5+11C5
Step-by-step explanation:
Well there are 17 and chooses 5 that's 17C5
there are 11 men abd chooses 5 that's 11C5
so add them up
17C5+11C5