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Anestetic [448]
2 years ago
8

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

hysical activity. What sample size should be obtained if she wishes the estimate to be within two percentage points with 99​% ​confidence, assuming that ​(a) she uses the estimates of 21.2​% male and 19.7​% female from a previous​ year? ​(b) she does not use any prior​ estimates?
Mathematics
1 answer:
Oliga [24]2 years ago
7 0

Answer:

no of sample within two percentage points  is 5409

no of sample not use prior​ estimates is 8321

Step-by-step explanation:

Given data

E = 2% = 0.02

male m = 21.2 % = 0.212

female f = 19.7 % = 0.197

to find out

no of sample within two percentage points and if does not use any prior​ estimates

solution

first we calculate no of sample within two percentage points

we know Z critical value for 99% is 2.58

so no of sample will be

n = (Z / E )² × m(1-m) + f ( 1-f )

put all the value we get no of sample

n = (2.58 / 0.02 )² × 0.212 ( 1 - 0.212 ) + 0.197 ( 1 - 0.197 )

n =  16641 ×0.3250

no of sample within two percentage points  is 5409

in 2nd part no of sample not use prior​ estimates

here than f and m will be 0.5

than

n = (Z / E )² × m(1-m) + f ( 1-f )

put all value

n = (2.58 / 0.02 )² × 0.5 ( 1 - 0.5 ) + 0.5 ( 1 - 0.5 )

n =  16641 ×  0.5

no of sample not use prior​ estimates is 8321

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The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot
Stells [14]

Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:  

Null hypothesis:p\leq 0.72  

Alternative hypothesis:p > 0.72  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

3 0
2 years ago
Select all equations that are equivalent to 5x + 6/2= 3-(4x +12)​
Savatey [412]

Answer:

- 4/3

Step-by-step explanation:

6 0
2 years ago
On the first day in each month, Enid deposited $4 into her bank account and Jim deposited $3 into his. They opened these account
ohaa [14]

Answer:

The amount of money in Enid bank account can be written as a linear equation.

Ye = Xe + $4*m

where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.

For Jim, the equation is similar:

Yj = Xj + $3*m

where Yj and Xj are similar as above.

Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).

Then we have that:

Ye = $72 = Xe + $4*7 = Xe + $28

Xe = $72 - $28 = $44

So in May 15, Enid deposited $44.

For Jim we have:

Yj = $72 = Xj + $3*7 = Xj + $21

Xj = $72 - $21 = $51

So in May 15, Jim deposited $51.

5 0
2 years ago
Two positive integers have a sum of 23 and a product of 126. Find the two numbers.
meriva

Answer:

SUBTRACT

Step-by-step explanation:

6 0
3 years ago
Equivalent expression of (m^1/3m^1/5)^0
Lapatulllka [165]

Answer:

\large\boxed{\left(m^\frac{1}{3}m^\frac{1}{5}\right)^0=1\ \text{if}\ m\neq0}

Step-by-step explanation:

\text{We know}\\\\a^0=1\ \text{for all value of}\ a\ \text{except 0}\\\\\left(m^\frac{1}{3}m^\frac{1}{5}\right)^0=1\ \text{if}\ m\neq0

7 0
3 years ago
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