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Anestetic [448]
2 years ago
8

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

hysical activity. What sample size should be obtained if she wishes the estimate to be within two percentage points with 99​% ​confidence, assuming that ​(a) she uses the estimates of 21.2​% male and 19.7​% female from a previous​ year? ​(b) she does not use any prior​ estimates?
Mathematics
1 answer:
Oliga [24]2 years ago
7 0

Answer:

no of sample within two percentage points  is 5409

no of sample not use prior​ estimates is 8321

Step-by-step explanation:

Given data

E = 2% = 0.02

male m = 21.2 % = 0.212

female f = 19.7 % = 0.197

to find out

no of sample within two percentage points and if does not use any prior​ estimates

solution

first we calculate no of sample within two percentage points

we know Z critical value for 99% is 2.58

so no of sample will be

n = (Z / E )² × m(1-m) + f ( 1-f )

put all the value we get no of sample

n = (2.58 / 0.02 )² × 0.212 ( 1 - 0.212 ) + 0.197 ( 1 - 0.197 )

n =  16641 ×0.3250

no of sample within two percentage points  is 5409

in 2nd part no of sample not use prior​ estimates

here than f and m will be 0.5

than

n = (Z / E )² × m(1-m) + f ( 1-f )

put all value

n = (2.58 / 0.02 )² × 0.5 ( 1 - 0.5 ) + 0.5 ( 1 - 0.5 )

n =  16641 ×  0.5

no of sample not use prior​ estimates is 8321

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