E^2x -2e^x -8=0   =>    e<span>^(2x)  -2e^x -8=0
Temporarily replace e^x with y.
Then (y)^2 - 2y - 8 = 0.  Factors are (y-4) and (y+2).
Roots are y = 4 and y= -2.
Now remembering that we temporarily replaced e^x with y, we let 
y=4 = e^x.  We need to solve for x.  Taking the natural log of both sides, we get:
ln 4 = x (answer)
We have to discard the other root (y= -2), because we cannot take the ln of a negative number.
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Answer is:<span>
= <span><span>48<span>y7 -</span></span> <span>5<span>y.</span></span></span></span>
        
             
        
        
        
Answer:
140?
Step-by-step explanation:
40 percent of 350 is 140 so I assume its 140.