All categories

3 years ago

How do you write the expression without a fraction bar; a to the seventh/a to the tenth

Mathematics

1 answer:

Len [333]3 years ago

4 0

$\frac{\frac{1}{7}}{\frac{1}{10}}=\frac{1}{7}:\frac{1}{10}=\frac{1}{7}\cdot\frac{10}{1}=\frac{10}{7}=1\frac{3}{7}$

You might be interested in

If y=15 when x=3/4, find x when y =25. Show work please!

-BARSIC- [3]

Set up a proportion: x/y = x/y

(.75)/(15) = (x)/(25)

Then cross multiply:

(.75)(25) = (15)(x)

18.75 = 15x

x = 1.25 or (5/4)

There you go :)

6 0

3 years ago

Who baked more cookies per batch?

Gnom [1K]

Jenny does, she bakes 12 for every x and dan bakes 10 for every x.
So in conclusion jenny bakes more cookies per batch

5 0

3 years ago

Read 2 more answers

If ABC FMU, what is the length of MU ?

alina1380 [7]

Fu/ac=mu/bc so 27/36=mu/24 so mu= 18

4 0

3 years ago

Al fotocopiar una credencial, primero se amplia al triple y posteriormente la copia resultante se reduce a la mitad. ¿Cual es el

ad-work [718]

Using google translate:
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?

Original: 10 by 6 cm ; Area = length * width = 10 x 6 = 60 cm²

first copy: enlarged to triple
10 x 3 = 30
6 x 3 = 18
30 x 18 = 540 cm²

second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²

7 0

3 years ago

15 points. Please answer as soon as possible.

abruzzese [7]

Answer:

A. $\frac{(a-b)^{2} +b^{2} }{a^{2}}$

Step-by-step explanation:

So to get the area of a square, we need to find the length of one side.

We know the length of the larger square is a, so the area of the larger cube is $a^{2}$

We can find the length of a side of the smaller square by using pythagoreans theorem to find the hypotenuse of the triangle formed in the bottom left corner. The length of one side along the x axis is a - b, and the length of the other side, along the y-axis, is b.

We can plug it into pythagoreans theorem to get

$(a-b)^{2} +b^{2} = C^{2}$ (C represents the length of one side of the smaller square, and the hypotenuse of the triangle)

$C = \sqrt{ (a-b)^{2} +b^{2}}$

The area of the smaller triangle is C squared to the area of the smaller triangle is

$(a-b)^{2} +b^{2}$

To get the ratio of the smaller square in comparison to the larger square we divide the area of the smaller square by the area of the larger square.

So the ratio should be

$\frac{(a-b)^{2} +b^{2} }{a^{2}}$

8 0

3 years ago