3 years ago

Can someone please help me with my math homework!!

Mathematics

1 answer:

larisa [96]3 years ago

3 0

1.)11x^2-3x
2.)8x+1-x^2
3.)-x^2-x+8
4.)-2y+10-x^2

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if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?

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Answer:

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

${h}^{2} = {p}^{2} + {b}^{2}$

plug the values

${h}^{2} = {(3 \sqrt{2} )}^{2} + {(2 \sqrt{3} )}^{2}$

To raise a product to a power, raise each factor to that power

${h}^{2} = 9 \times 2 + 4 \times 3$

Multiply the numbers

${h}^{2} = 18 + 12$

Add the numbers

${h }^{2} = 30$

Take the square root of both sides of the equation

$h = \sqrt{30}$

Hope this helps...

Best regards!!

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