Using the binomial distribution, it is found that there is a 0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.
For each household, there are only two possible outcomes. Either it has at least one VCR, or it does not. The probability of a household having at least one VCR is independent of any other household, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 14 households, hence
.
- 0.535 probability of having at least one VCR, hence
.
The probability of <u>at least 6 and no more than 8</u> is:
In which:
Then:
0.5601 = 56.01% probability that the number having at least one VCR is no more than 8 but at least 6.00.
A similar problem is given at brainly.com/question/24863377