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babymother [125]
3 years ago
11

Why do X-Ray technicians stand behind a shield when giving X-Rays to patients?

Physics
2 answers:
scoray [572]3 years ago
7 0
Lol I just learned this, here's the short answer:
Large doses of X-Rays are known to cause cell damage and cancer, so
<span>X-Ray technicians have to stand behind the shield. Here's the lengthy answer:
</span> This is because the patient would only be exposed to the small dose of radiation once, which is hardly harmful. However, radiographers deal with this all day every day, which could mean that the small doses could add up. This is why they stand behind a lead screen; the small exposure to the X-Rays aren't harmful alone but frequent exposure could begin to damage your cells and lead to potential genetic mutation. If a patient is often in radiography (a long-stay patient for example), they begin to wear lead aprons whilst being X-rayed in order to prevent the risk of harm. Hope I answered correctly.



Mashcka [7]3 years ago
7 0

Answer:

because large doses of X-Rays are known to cause cell damage and cancers

Explanation:^^

You might be interested in
relationship beetween image distance,focal length ,power magnification, for both concave and convex lens.​
scoray [572]

Answer:

Object distance means what is the distance between pole and object. Image distance means when image is formed then the distance between pole and image is called image distance. Focal length is the distance between pole and the principal focus of the mirror.

A lens is a clear object, usually made of glass or plastic, which is used to refract, or bend light. Lenses can concentrate light rays (bring them together) or spread them out. Common examples of lenses include camera lenses, telescope lenses, eyeglasses, and magnifying glasses. Lenses are often double lenses, meaning they have two curved sides. A convex lens is rounded outward, while a concave lens curves inward. (A great way to remember this is that a concave lens creates an indent like a cave!)

The image distance can be calculated with the knowledge of object distance and focal length with the help of lens formula. In optics, the relationship between the distance of an image (i), the distance of an object (o), and the focal length (f) of the lens are given by the formula known as Lens formula. Lens formula is applicable for convex as well as concave lenses. These lenses have negligible thickness. It is an equation that relates the focal length, image distance, and object distance for a spherical mirror. It is given as,

1/i + 1/o = 1/f

i= distance of the image from the lens

o= distance of the object from the lens

f= focal length of the lens

Explanation:

Hope it is helpful....

7 0
3 years ago
Read 2 more answers
Floodplains are most often found for rivers that exist on
Kazeer [188]
I am pretty sure that floodplains are most often found for rivers that exist on <span>
hilly areas at the base of mountains. In order to give yoy ans example which will make sure that this answer is quite a suitable one, nice example of f</span><span>loodplains</span>
is The Virgin River<span> at the upper end of Zion Canyon. It will definitely help you! Regards.</span><span>

</span>
3 0
3 years ago
Read 2 more answers
What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your an
AveGali [126]

Complete Question

A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.

What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.

Answer:

\phi=123.75

Explanation:

From the question we are told that:

Height h=27m

Period T=32sec

Time t=75sec

Generally the equation for angular velocity is mathematically given by

\omega=\frac{2 \pi}{T}

\omega=\frac{2 \pi}{32}

\omega=0.196rad/s

Therefore

\theta=\omega t

\theta=0.196rad/s*75sec

\theta=843.75 \textdegree

Therefore

\phi=\theta-2(360)

\phi=123.75

6 0
3 years ago
which statement best describes what would happen if the number of wore coils in a electromagnavneg were increased
jekas [21]
Where are the following choices
4 0
3 years ago
On a clear day at a certain location, a 119-V/m vertical electric field exists near the Earth's surface. At the same place, the
IrinaVladis [17]

Answer:

(a) 62.69 nJ/m^3

(b) 1015.22 μJ/m^3

Explanation:

Electric field, E = 119 V/m

Magnetic field, B = 5.050 x 10^-5 T

(a) Energy density of electric field = \frac{1}{2}\varepsilon _{0}E^{2}

          =\frac{1}{2}\times 8.854\times 10^{-12}\times 119\times 119

          = 6.269 x 10^-8 J/m^3 = 62.69 nJ/m^3

(b) energy density of magnetic field = \frac{B^{2}}{2\mu _{0}}

=\frac{\left ( 5.05\times 10^{-5} \right )^{2}}{2\times 4\times 3.14\times 10^{-7}}

= 1.01522 x 10^-3 J/m^3 = 1015.22 μJ/m^3

8 0
3 years ago
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