Answer:
As collision is elastic,thus we can use conservation of momentum equation
mA=0.2 kg
(vB)1=0 m/s.......................as it is on rest before collision
(vA)1=4 m/s
(vA)2=-1 m/s
(vB)2=2 m/s
using equation
(mA*vA+mB*vB)1= (mA*vA+mB*vB)2
Where 1 and 2 represents before and after collision
(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)
0.8=-0.2+(2mB)
mass of object B=mB=0.3 Kg
A=mgh
m=300g=0.3kg
g=9,81 m/s^2
h=10m
A=29.43J
I would said A is the best option if i’m wrong sorry
Answer:
0.2 T
Explanation:
Magnetic field is inversely proportional to the distance from wire since the distance is halved therefore magnetic field will be doubled.
A because of the resistors are four in this options first option is multiplied by 4
