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Ivenika [448]
3 years ago
9

Which graph shows the solution set of x-9/7x+2<=0

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0
For this case we have the following inequality:
 \frac{x-9}{7x+2}  \leq 0
 Solving for the numerator we have:
 x-9 \leq 0
 x  \leq 9
 Solving for the denominator we have:
 7x+2\ \textgreater \ 0
 7x\ \textgreater \ -2
 x \ \textgreater \   \frac{-2}{7}
 Therefore, the solution is given by:
 \frac{-2}{7} \ \textless \  x  \leq 9
 The graph that shows this solution is the graphic number 3.
 Answer:
 
option 3
Kazeer [188]3 years ago
3 0
We have that
<span>(x-9)/(7x+2)<=0

we know that
</span><span>the denominator cannot be zero, therefore the value of x = -2 /7 cannot belong to the domain of the function
</span>7x+2=0-----> x=-2/7-----> x=-0.29

using a graph tool
see the attached figure

the solution is the interval
(-2/7, 9]---------> (-0.29, 9]
the value of -0.29 is not included in the solution

therefore 
the answer is the third option
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What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

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From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

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