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3 years ago

7 times what equals 1?

2 answers:

4 0

For this case, the first thing we must do is define a variable.
We have then:
x: unknown number
Doing the multiplication we have:
$(7) (x) = 1
$
From here, we clear the value of x.
We have then:
$x = \frac{1}{7} 
$
Therefore, we have:
$(7) ( \frac{1}{7} ) = 1
$
Answer:
7 times 1/7 equals 1

Novosadov [1.4K]3 years ago

4 0

The answer is 1/7.
If you do 7/1 times 1/7
7 times 1 equals 7
1 times 7 equals 7
7/7 when simplified is 1

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Do reflections have the same orientation? In other words, if a shape is reflected, do both figures still have the same orientati

melisa1 [442]

Answer:

I think so.

Step-by-step explanation:

With letters, no, and some shapes would be reversed, like a triangle with lengths that are all different from eachother.

4 0

3 years ago

The length of a rectangle is 6 cm longer than its width.

oksian1 [2.3K]

2(6+w)+2(w)=40
12+2w+2w=40
12+4w=40
4w=28
w=7
Now we know that the width is 7; abd the length is 7+6 which is 13.
To find the area we multiply 13x7
The area is 92cm squared

4 0

3 years ago

Please help

nalin [4]

Answer:

12870ways

Step-by-step explanation:

Combination has to do with selection

Total members in a tennis club = 15

number of men = 8

number of women = 7

Number of team consisting of women will be expressed as 15C7

15C7 = 15!/(15-7)!7!

15C7 = 15!/8!7!

15C7 = 15*14*13*12*11*10*9*8!/8!7!

15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C7 = 15*14*13*12*11/56

15C7 = 6,435 ways

Number of team consisting of men will be expressed as 15C8

15C8 = 15!/8!7!

15C8 = 15*14*13*12*11*10*9*8!/8!7!

15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C8 = 6,435 ways

Adding both

Total ways = 6,435 ways + 6,435 ways

Total ways = 12870ways

Hence the required number of ways is 12870ways

4 0

2 years ago

If you had to add two fractions with denominators of 4 and 5. What might the denominator of the sum be? Show more than one possi

mylen [45]

Answer:

your answer would be 20 because you would find what both can go into.

5 0

3 years ago

A bag contains 6 red balls and 3 blue balls. 4 balls are selected at random. find the probability of selecting 4 red balls.

geniusboy [140]

Assuming that the balls are not replaced;

$\frac{6}{9}* \frac{5}{8}* \frac{4}{7}* \frac{3}{6}$ = 5/42

(the numbers are decreasing in the denominator as you are presumably taking out the red balls. In the denominator, there is one less ball each time since you took out a red one).

Therefore, the probability of selected 4 red balls consecutively without replacement is 5/42.

Hope I Helped :)

4 0

3 years ago