37:prime 65:composite 71:composite 82:composite
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
Answer:
Multiply the second equation by −2 to get −8x − 6y = −30.
Step-by-step explanation:
{2x + 6y = 12
{4x + 3y = 15
{2x + 6y = 12
{−8x − 6y = −30 >> New Equation
* Doing this will give you <em>additive</em><em> </em><em>inverses</em><em> </em>of −6y and 6y, which result in 0, so they are both ELIMINATED.
** [3, 1] is your solution.
I am joyous to assist you anytime.
I think It is be but idk as I am in year 7