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irinina [24]
3 years ago
5

Is a "solution" another term for zeros?

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Answer:

No

Step-by-step explanation:

because its not a generally vector-valued function

HACTEHA [7]3 years ago
4 0

Answer:

  Not necessarily

Step-by-step explanation:

A "solution" and a "zero" are the same thing for the equation ...

  f(x) = 0

For anything else, such as ...

  f(x) = 1

a zero of f(x) is <em>not a solution</em>.

_____

All equations can be put into the form

  f(x) = 0

so a zero will be a solution to it. I often use this form with a graphing calculator, because those are adept at finding zeros.

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Side length of cube with volume of 729 ft
navik [9.2K]
The answer is 9, hope this helped <3
6 0
3 years ago
2. A man buys eggs at 55kobo a score . he finds that 10% of the eggs are unsellable but sells the rest at 60kobo a dozen .find i
liubo4ka [24]

Answer:

Percentage Profit is 63.63%

Step-by-step explanation:

The man buys 440 eggs at 55 pence a score

i.e. he buys 20 eggs for 55 pence

He buys 1 egg for 55/20 = 2.75 pence

Therefore, he buys 440 eggs for = 440 × 2.75 = 1210 pence

10% eggs are unsaleable

thus he sold = 440 - 440 × 10/100 = 440 - 44 = 396 eggs

Eggs sold in dozen = 396/12 = 33

He sold 1 dozen for = 60 pence

Thus, he sold 33 dozen for = 33 × 60 = 1980 pence

Profit = 1980 - 1210 = 770 pence

% Profit = (770/1210) × 100 = 63.63%

(hope this helps can i plz have brainlist :D hehe)

3 0
3 years ago
Describe the translation 7 units to the left, 12 units up using a vector.
Lelu [443]
The magnitude of the vector is √(7^2+12^2)=√(49+144)=√193

The direction is α=arctan(y/x)=arctan(12/-7)≈-59.74 however this is relative to the negative x-axis so we add 180° to get the standard angle...180-59.74=120.26°

So the vector is √193 @ 120.26°
5 0
3 years ago
Identify the class width for the given frequency distribution
Fittoniya [83]

Answer: not enough information

Step-by-step explanation:

6 0
3 years ago
Solve the equation without the use of a calculator. please Help!!! Thank you!!!<br> 12x^3-30x=5-2x^2
nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

2x^2-5 = 0 \implies \\ 2x^2=5 \implies\\ x^2=\frac{5}{2} \implies\\ x=\pm\frac{\sqrt{5}}{\sqrt{2}}=\pm\frac{\sqrt{10}}{2} \\ \\ 6x+1 =0 \implies \\ 6x=-1 \implies\\ x=\frac{-1}{6}

So, our solutions are:

x\in \{\frac{\sqrt{10}}{2},-\frac{\sqrt{10}}{2},-\frac{1}{6}\}

4 0
3 years ago
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