Answer:
Strong broad peak around 3200-3600 cm-1 should be present
Strong peak around around 1700 cm-1 should be absent
Explanation:
Infrared spectroscopy is an analytical technique which is used for molecular structure characterization by identifying the functional groups present in a given molecule based on the absorption wavelength (or wavenumber).
In an IR spectrum the carbonyl group is associated with the C=O stretch which occurs as a strong peak around around 1700 cm-1. For alcohol the -corresponding O-H stretching frequency occurs as a strong broad peak between 3200-3600 cm-1.
Therefore, in the case of estradiol the presence a strong broad peak in the 3200-3600 cm-1 and the absence of the peak at around 1700 cm-1. would suggest that the transformation is complete.
Answer: if ur talking abt a project,
yes, there will have to be a way to see how it looks like so it can't be a full box. so like the front or the top or anything has to be cut.
plus, if the water cycle itself would have to be printed to be a box shape
if not in a box shape, it can be inside a box. that would make it any shape but it's still in a box.
Explanation:
Answer:
personality it’s not about looks or how much you wiegh or anything all that doesn’t matter it’s all about what’s on the inside none of that matters if you have a good personality:)
Explanation:
The diagram below shows three types of earthquake waves, labeled A, B, and C at different time intervals. The statement that is correct about the three waves is <span>Wave A and Wave B are absorbed by liquid medium. The answer is letter B.</span>
Answer:
Explanation:
Utilizing Rydber's equation:
ΔE = Z²Rh ( 1/n₁² - 1/n₂²) and substituting the values given ( using the Rydbers constant value in Joules ), we have
n=1 to n= infinity
ΔE = 3² x (1/1² - 0) x 2.18 x 10⁻^18 J = 2.0 x 10⁻¹⁷ J (1/infinity is zero)
n= 3 to n= infinity
ΔE = 3² x (1/3² - 0) x 2.18 x 10⁻^18 J = 2.28 x 10^-18 J
b. The wavelength of the emitted can be obtained again by using Rydberg's equation but this time use the constant value 1.097 x 10⁷ m⁻¹ given in the problem .
1/λ = Z²Rh (1/n₁² - 1/n₂²) 10 ⁻¹ = 3² x 1.097 x 10⁷ m⁻¹ x (1/1² - 1/3²) m⁻¹
1/λ =8.8 x 10⁷ m⁻¹ ⇒ λ =1.1 x 10^-8 m
λ = 1.1 x 10^-8 m x 1 x 10⁹ nm/m = 11 nm
