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3 years ago

13

What ions are associated with acids

2 answers:

aivan3 [116]3 years ago

6 0

Hydrogen ions (H+) are associated with acids.

kondor19780726 [428]3 years ago

4 0

Blank de clan be hope she's helps youuuuuu

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Does radiation count as an electromagnetic wave, and if so what would it be called?

guapka [62]

No. Radiation is not in the magnetic “criteria” so it would not be correct.

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4 years ago

A simple machine produces 25 joules of output work for every 50 joules of input work . What is the efficiency of this machine ?

nataly862011 [7]

2:1, output is half the input

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3 years ago

32.Alpha particles and beta particles differ in

Aleks04 [339]

The answer is C. Alpha particles are simply helium-4 nuclei, with 2 protons and 2 neutrons. Charge is 2+, and mass is on the order of 4amu. Beta particles are either electrons or positrons, with charges of 1- and 1+ respectively. Their masses are fractions of amu, so alpha particles and beta particles differ in both mass and charge.

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4 years ago

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4 grams of carbon react with an unlimited amount of H2O. The reaction is: C + H2O → CO + H2is the equation balanced?

shepuryov [24]

<span> C + H2O → CO + H2 - this reaction is balanced,
1 mol C 1 mol C
2 mol H 2 mol H
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4 years ago

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Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?

nadya68 [22]

Answer:

$2.82\cdot 10^9 y$

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

$m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}$ (1)

where

$m_0$ is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

$\tau$ is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

$\tau=7.04\cdot 10^8 y$

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

$\frac{m(t)}{m_0}=\frac{6.25}{100}$

Substituting into (1) and solving for t, we can find how much time has passed:

$t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y$

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4 years ago