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Vinvika [58]
3 years ago
11

The major difference between real and nominal GDP is that real GDP

Chemistry
1 answer:
I am Lyosha [343]3 years ago
3 0

C). Real GDP is adjusted for price level changes, whereas nominal GDP is not.

<h3>Explanation</h3>

The GDP of a country measures the total value of all final goods and services produced within that country in a certain period of time (typically a year.)

Real GDP is based on nominal GDP, but takes changes in the overall price level into account as well. That's why the two indice are so similar, except for that the value of real GDP but not nominal GDP can be compared over a period of many year to show economic growth.

  • Neither real GDP nor nominal GDP measure debt, which isn't part of the output of an economy.
  • Both real GDP and nominal GDP take the value of exports into account, as long as the good being sold abroad is made inside that country. Net export is also one of the four types of spendings on the output of an economy.
  • Only real GDP is adjusted for changes in the price level. <em>This point sets real and nominal GDP apart.</em>
  • Neither real GDP nor nominal GDP counts intermediate goods. To avoid counting the same good or service twice, both indice measure only the value of final goods and services.
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Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50Ti (5.3%). What is the average atomic
NNADVOKAT [17]

Hey there!:

Isotopes :                          abundance :

46 Ti                                       8.0%

47 Ti                                        7.8 %

48 Ti                                      73.4 %

49 Ti                                       5.5 %

50 Ti                                         5.3 %

Weighted average =   ∑ Wa * % / 100

Therefore:

( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =

4792.3 / 100

= 47.923 a.m.u


       Hope that helps!

7 0
3 years ago
Calculate the number of moles of KOH in 6.70 mL of a 0.480 M KOH solution. (Enter your answer in scientific notation.)
andrew-mc [135]

Answer:

3.2×10^-3 mol

Explanation:

The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.

The question gives you the volume in mL, so to convert "mL" to "L" you need to divide by 1000. (6.70mL/ 1000L)= 0.0067L.

Now you can plug the numbers into the equation. 0.480M= n/ 0.0067L), multiply (0.480M×0.0067L)= 0.003216 mol. The scientific notation is 3.2×10^-3, 10^-3 because you move the decimal back three times and 3.2 because there are 2 sig figs.

5 0
3 years ago
CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
padilas [110]

<u>Answer:</u> The \Delta G for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm

Putting values in above equation, we get:

K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85

To calculate the gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol

Hence, the \Delta G for the reaction is 54.425 kJ/mol

7 0
3 years ago
What reactions are responsible for the glow and heat from the sun? nuclear fission nuclear fusion chemical reactions atomic disi
Mamont248 [21]
Nuclear Fusion is the answer to the question who posted.

7 0
3 years ago
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Any single type of substance
ra1l [238]

Answer:

weed

Explanation:

3 0
4 years ago
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