I know my cases are f(0,0), f(0,1), f(0,2), f(0,3), f(1,0), f(1,1), f(1,2), f(1,3), f(2,0), f(2,1), f(2,2), f(2,3), f(3,0), f(3,1), f(3,2), f(3,3) and that:<span>
0≤x+y≤3</span><span>
since there are 3 cards being drawn we cannot have more than 3 jacks or 3 kings or combination of 3 of the two, or 0 jacks and 0 king
</span>
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Answer:
x² + 8x + 7
General Formulas and Concepts:
<u>Algebra I</u>
- Terms/Coefficients/Degrees
- Expand by FOIL (First Outside Inside Last)
Step-by-step explanation:
<u>Step 1: Define</u>
(x + 7)(x + 1)
<u>Step 2: Expand</u>
- Expand [FOIL]: x² + x + 7x + 7
- Combine like terms: x² + 8x + 7