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xxTIMURxx [149]
3 years ago
14

What is the simplest form of the following expression?

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
\sqrt[3]{ \frac{12x ^{2} }{16y} } =  \sqrt[3]{\frac{3x ^{2} }{4y} }
sweet-ann [11.9K]3 years ago
5 0

Answer:

The simplest form of the following expression is \sqrt[3]{\frac{3x^2}{4y}}

Step-by-step explanation:

The given expression is

\sqrt[3]{\frac{12x^2}{16y}}

Factor the numerator and denominator.

\sqrt[3]{\frac{3\times 4\times x^2}{4\times 4\times y}}

3 is common factor. Cancel out the common factor.

\sqrt[3]{\frac{3\times x^2}{4\times y}}

\sqrt[3]{\frac{3x^2}{4y}}

Therefore the simplest form of the following expression is \sqrt[3]{\frac{3x^2}{4y}}.

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const2013 [10]
If a logarithm has a coefficient, then the coefficient can also be written as the exponent of the input of the logarithm. In other words, if you have the logarithm alog(x), that is equal to log(x^a). So the expression can be rewritten:

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If tow logarithms of the same bases are added together that is equal to the logarithm of the product of the inputs of the two original logarithms. In other words, given log(x)+log(y), it can also be written as log(xy). So the expression can be combined into one logarithm:

log(x^2 * y^3)
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Rewrite using a single positive exponent.<br> 6^5<br> 6
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Answer:

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