It's C first find 3/5 of the horoziotal
An=a1r^(n-1)
given
a5=1/24
a10=1/768
we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)
so
1/24=a1r^4
1/768=a1r^9
(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32
r^5=1/32
take 5th root of both sides
r=1/2
we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3
the first term is 2/3
Answer:
a reflection over the x-axis and then a 90 degree clockwise rotation about the origin
Step-by-step explanation:
Lets suppose triangle JKL has the vertices on the points as follows:
J: (-1,0)
K: (0,0)
L: (0,1)
This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:
J: (0,1) , K: (0,0), L: (1,0)
Then we reflect it across the y-axis and get:
J: (0,1), K:(0,0), L: (-1,0)
Now we go through each answer and look for the one that ends up in the second quadrant;
If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.
If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.
If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.
The third answer is the only one that yields a transformation which leads back to the original position.
