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3 years ago

4(x-12)^1/3 = -16 Help please, thank you

Mathematics

1 answer:

Lina20 [59]3 years ago

7 0

Hello!

4 (x-12) ^ 1/3 = -16

Step 1. Simplify each side of the equation, 4/ 3x + −16 = −16 and 4 /3 x −16 = −16

Step 2. Add 16 to both sides, 4 /3 x − 16 + 16 = −16 + 16

Step 3: Multiply both sides by 3/4, ( 3/4)*(4/3x)=(3/4)*(0)

Final Answer: x= 0

Hope I could help! :)

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May you solve this for me?

shusha [124]

Answer: 23.94 cm

Step-by-step explanation: I am totally not sure if this is the answer, but think of it this way: Those are 2 semi circles. The formula for the area of a semi circle is A = π * r^2 / 2. For the semi circle with 6 cm, the radius is 3. So we can plug it in the formula. 3.14 * 3^2 / 2, which is 14.13. For the semi circle with 5 cm, the radius is 2.5. Again plug it in and it will be 3.14 * 2.5^2 / 2, which is 9.8125. Then, to get the total area, add the 2 final values together. 9.8125 + 14.13, which is 23.9425. Then it said "round to the nearest hundredth if necessary. We can round to the nearest hundredth, which is 23.94, so that would be the answer. That is just my thought process.

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2 years ago

When temperature is zero degree Celsius, the Fahrenheit temperature is 32. When the Celsius temperature is 100, the correspondin

7nadin3 [17]

Answer:

$\\ y = 1.8(x) + 32$ or $\\ y = \frac{9}{5}(x) + 32$

or equivalently:

$\\ F = 1.8(C) + 32$ or $\\ F = \frac{9}{5}(C) + 32$

Step-by-step explanation:

To express the Fahrenheit temperature as a linear function of the Celsius temperature, F(c), we can proceed as follows.

We can use here the two-point form equation of a line:

$\\ y-y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x-x_1)$ [1]

We are asked to express the Fahrenheit temperature as a function of Celsius temperature, so the independent variable, in this case, is x (Celsius temperature) and the dependent variable is y (Fahrenheit temperature).

When temperature is zero degree Celsius ( $\\x_1 = 0$ ), the Fahrenheit temperature is 32 ( $\\y_1 = 32$ ).

When the Celsius temperature is 100 ( $\\x_2 = 100$ ), the corresponding Fahrenheit temperature is 212 ( $\\y_2 = 212$ ).

Then, using [1], we have:

$\\ y-32 = \frac{212 - 32}{100 - 0}(x-0)$

$\\ y-32 = \frac{180}{100}(x)$

$\\ y-32 = 1.8(x)$ .

It could be also be written as:

$\\ y-32 = \frac{18}{10}(x)$ = $\\ y-32 = \frac{9}{5}(x)$ , as it commonly appears in books.

Then the Fahrenheit temperature express as a linear function of the Celsius temperature, F(c) is ( solving the equation for y ) :

$\\ y = 1.8(x) + 32$ or $\\ y = \frac{9}{5}(x) + 32$ .

Or equivalently:

$\\ F = 1.8(C) + 32$ or $\\ F = \frac{9}{5}(C) + 32$

We can check this using the given values from the question:

For 0 Celsius degrees, the Fahrenheit temperature is:

$\\ y = 1.8(0) + 32$ = 32 Fahrenheit degrees.

For 100 Celsius degrees, the Fahrenheit temperature is:

$\\ y = 1.8(100) + 32 = 180 + 32$ = 212 Fahrenheit degrees.

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